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What is the effect on the current in a wire if both the voltage across it and its resistance is halved?

What is the effect on the current in a wire if both the voltage across it and its resistance is halved?

The number one law in circuit analysis is Ohm’s law: V = IR. Under this relationship, if voltage doubles and resistance halves, you will get 4x the original current. (ie, 10 V across 20 ohms of resistance would produce 0.5 amps of current, 20 V across 10 ohms of resistance would produce 2 amps of current).

What will happen to the current flowing through the circuit if the voltage across it is doubled?

if you increase the voltage (or electrical pressure) in a circuit then the current (flow of electrons) will increase in direct proportion, eg if you double the voltage the current flow will double.

What is the effect on current through a circuit of steady resistance when the voltage is doubled?

Using Ohms law, if resistance is constant the the current will be proportional to applied voltage. So if voltage is doubled the current is also doubled.

How will the current change if the voltage in a circuit is held constant while the resistance halves?

This means that as the voltage increases, current increases and as the resistance increases, current decreases. So in your scenario, if the voltage remains the same, but the resistance is doubled, that means that the current will be halved.

What if both voltage and resistance are doubled?

and if the voltage and the resistance both are doubled, the current will not change. and if the voltage and the resistance both are doubled, the current will not change.

What happens when voltage is constant and resistance increases?

If the current is held constant, an increase in voltage will result in an increase in resistance. Alternately, an increase in current while holding the voltage constant will result in a decrease in resistance.

What happens to the power of a battery when voltage doubles?

Since P=VI, and since the current doubles when the voltage doubles, the power increases by a factor of 4. A battery is hooked up to a lightbulb, as shown in the figure.

Why does heating a metal wire increase or decrease its electrical resistance?

Does heating a metal wire increase or decrease its electrical resistance? Why? It decreases resistance because atoms at higher temperatures jostle into the way of moving electrons. It decreases resistance because higher temperatures free more electrons to carry current.

How is the current flowing through a circuit containing two lightbulbs?

The current flowing through the circuit containing two lightbulbs is _________. The resistance of two identical resistors in series is twice the resistance of one resistor. Since the current is proportional to the inverse of the resistance, the current is half as much as the circuit with one resistor.

What is the magnitude of the current flowing through bulb # 2?

The magnitude of the current flowing through bulb #2 is ___________. A battery is hooked up to a lightbulb, as shown in the figure. If the voltage difference of the battery were doubled, the resulting electric power would ______. Since P=VI, and since the current doubles when the voltage doubles, the power increases by a factor of 4.

What happens to resistance when voltage is halved?

In other words, resistance rises with rising temperature. So at half the voltage, the resistive element won’t heat up as much, so the resistance will be lower. The current will still be less than it would be at full voltage, but more than half.

Since P=VI, and since the current doubles when the voltage doubles, the power increases by a factor of 4. A battery is hooked up to a lightbulb, as shown in the figure.

What happens to the current in a resistive circuit?

If it is a resistive circuit but there is a temperature induced change, the current may drop to something more than half. Most heating elements and all incandescent light bulbs have a positive temperature coefficient. In other words, resistance rises with rising temperature.

The current flowing through the circuit containing two lightbulbs is _________. The resistance of two identical resistors in series is twice the resistance of one resistor. Since the current is proportional to the inverse of the resistance, the current is half as much as the circuit with one resistor.

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Ruth Doyle