How is air drag related to the torque?

How is air drag related to the torque?

Air drag is even worse, proportional to the square of the speed. Second, the power required is the speed times the torque. In a ideal system with no friction, the torque to maintain 10 m/s and 1000 m/s is the same, but the power required to produce that torque at the higher speed is 100 times more.

How much torque do you need at 1000 m / s?

In a ideal system with no friction, the torque to maintain 10 m/s and 1000 m/s is the same, but the power required to produce that torque at the higher speed is 100 times more. If you needed 15 W at 10 m/s, then you’ll need 1.5 kW at 1000 m/s. – Olin Lathrop Apr 19 ’16 at 21:46 thank you so much!!! You were very very very clear!

How do I achieve required torque when using an impact driver?

I only care of achieving more or less the required torque – so that the nuts don’t loosen on themselves and parts are not damaged while the nuts are being tightened. The primary concern is that the driver works very fast, so if I hold the switch pressed for just too long I can easily overtighten the nut and cause unintended damage.

How much torque do you need to accellerate a mass?

To get the real torque required, you have to specify how fast you want to be able to accellerate this mass upwards. For example, let’s say you need at least 3 m/s². Solving Newton’s law of F = ma: That, in addition to the 4.4 N just to balance gravity means you need 5.8 N upwards force. At 0.05 m radius, that comes out to a torque of 0.28 Nm.

Air drag is even worse, proportional to the square of the speed. Second, the power required is the speed times the torque. In a ideal system with no friction, the torque to maintain 10 m/s and 1000 m/s is the same, but the power required to produce that torque at the higher speed is 100 times more.

In a ideal system with no friction, the torque to maintain 10 m/s and 1000 m/s is the same, but the power required to produce that torque at the higher speed is 100 times more. If you needed 15 W at 10 m/s, then you’ll need 1.5 kW at 1000 m/s. – Olin Lathrop Apr 19 ’16 at 21:46 thank you so much!!! You were very very very clear!

I only care of achieving more or less the required torque – so that the nuts don’t loosen on themselves and parts are not damaged while the nuts are being tightened. The primary concern is that the driver works very fast, so if I hold the switch pressed for just too long I can easily overtighten the nut and cause unintended damage.

To get the real torque required, you have to specify how fast you want to be able to accellerate this mass upwards. For example, let’s say you need at least 3 m/s². Solving Newton’s law of F = ma: That, in addition to the 4.4 N just to balance gravity means you need 5.8 N upwards force. At 0.05 m radius, that comes out to a torque of 0.28 Nm.