Which indicator is used in the titration of NaOH and HCl?
Which indicator is used in the titration of NaOH and HCl?
phenolphthalein
In the titration of HCl against NaOH, phenolphthalein is used as suitable indicator.
What indicates the end point of a titration?
The end point of a titration is the point at which the indicator changes color. When phenolphthalein is the indicator, the end point will be signified by a faint pink color.
What indicator will be used in the HCl and NaOH titration experiment provided in the lab manual?
The titrant is a standard solution of sodium hydroxide. The indicator is phenolphtalein, and it is added to the acid, or in this case, the analyte. This is because it is colorless in an acid, but pink in basic solutions.
What is the conclusion of titration experiment?
In the process of titration, a basic solution is gradually added to the acidic solution until complete neutralization is obtained. The ‘end point’ of the titration is detected with the help of an indicator as color of the solution changes upon neutralization.
What happens when HCl is titrated with NaOH?
Consider this example in which a sample of hydrochloric acid (HCl) is titrated with sodium hydroxide (NaOH). As it is added, the HCl is slowly reacted away. The point at which exactly enough titrant (NaOH) has been added to react with all of the analyte (HCl) is called the equivalence point.
Why is NaOH used in titration?
The volume of titrant added can then be determined by reading the level of liquid in the buret before and after titration. Titrant (NaOH) is added until it neutralizes all of the analyte (acetic acid). This is called the equivalence point.
What is the neutralization reaction for HCl reacting with NaOH?
Let’s see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCl → H2O and NaCl.
How do you find the molarity of NaOH from titration with HCl?
Step 1: Calculate the amount of sodium hydroxide in moles
- Amount of solute in mol = concentration in mol/dm 3 × volume in dm 3
- Amount of sodium hydroxide = 0.100 × 0.0250.
- = 0.00250 mol.
- The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H 2O(l)
- So the mole ratio NaOH:HCl is 1:1.
