What if engines were 100% efficient?
What if engines were 100% efficient?
It would be a great world if it wasn’t impossible. For engine to be 100% efficient, all input energy would need to be converted into useful output energy. The output of a 100% efficient engine would be all work & no heat, no pollution, no emissions, no noise or vibration.
Can there be an engine that is 100 percent efficient Why?
It is impossible for heat engines to achieve 100% thermal efficiency () according to the Second law of thermodynamics. This is impossible because some waste heat is always produced produced in a heat engine, shown in Figure 1 by the term.
Under what conditions would a heat engine be 100 efficient?
2nd law of thermodynamics speaks strictly about heat engines. For a heat engine, the highest possible efficiency (theoretically) is that of a Carnot engine. For the carnot cycle to have 100% efficiency the low heat reservoir must be absolute zero.
Can we consider heat engine 100 Efficient why why not Brainly?
Short answer: No. 100 percent efficient engine is not possible. In reality, heat engines are inefficient systems. Another is that not all thermal energy is used by the system, some of it exits the engine as heat, which is not used to produce the force or output that is needed.
Is there a 100% efficient machine?
The short answer is: It can’t. Almost all machines require energy to offset the effects of gravity, friction, and air/wind resistance. Thus, no machine can continually operate at 100 percent efficiency.
Are the engines 100% efficient if not what happens to the remaining percent?
The efficiency of a heat engine can be 100% only if all the heat energy gets converted into work (or mechanical energy). Since heat energy can never be transformed completely into mechanical energy, so the efficiency of a heat engine can never be 100 per cent.
How do you solve thermal efficiency?
The air-standard Otto cycle thermal efficiency is a function of compression ratio and κ = cp/cv. The thermal efficiency, ηth, represents the fraction of heat, QH, that is converted to work.
What do you think are the effects of excess heat coming from heat engine?
Since waste heat is a necessary product of heat engines, efficiencies of power plants are limited (see Carnot efficiency) and therefore must burn more fuels in order to achieve their desired energy output. This increases greenhouse gas emissions, and contributes more to global warming.
Is there any proof that Carnot cycle is the most efficient?
The only proof I have is showing the Carnot cycle is the most efficient and that is only 100% efficient if the cold reservoir is at absolute zero, which it can not be at. Is there any way to work from the statement: Δ S ≥ 0 (for any process in a closed system), to some result which says you can not achieve 100% efficiency?
Why is a cycle not a 100% efficient process?
That process converts heat to work at 100% efficiency. But a process is not a cycle. To operate in a cycle the system has to return to its original state. After the reversible isothermal expansion there is no way to return to the original state and do net work without rejecting some heat to a lower temperature reservoir.
Why is the mechanical efficiency of ice steel less than 1?
The mechanical efficiency itself must also be less than 1 due to mechanical losses in friction and unavoidable energy loss in forced cooling (water, air, or both) so as not to burn or distort the ICE steel combustion chamber. I assume the best modern efficiency that can be achieved from ICE is something near 0.5
Why is a heat engine cannot be 100% efficient?
4 Answers 4. The fact that a heat engine cannot be 100% efficient is a consequence of the Kelvin-Plank statement of the second law, which can be summarized as. Kelvin-Plank Statement of Second Law “No heat engine can operate in a cycle while transferring heat with a single heat reservoir” (my emphasis on cycle)
The only proof I have is showing the Carnot cycle is the most efficient and that is only 100% efficient if the cold reservoir is at absolute zero, which it can not be at. Is there any way to work from the statement: Δ S ≥ 0 (for any process in a closed system), to some result which says you can not achieve 100% efficiency?
That process converts heat to work at 100% efficiency. But a process is not a cycle. To operate in a cycle the system has to return to its original state. After the reversible isothermal expansion there is no way to return to the original state and do net work without rejecting some heat to a lower temperature reservoir.
The mechanical efficiency itself must also be less than 1 due to mechanical losses in friction and unavoidable energy loss in forced cooling (water, air, or both) so as not to burn or distort the ICE steel combustion chamber. I assume the best modern efficiency that can be achieved from ICE is something near 0.5
